[最も欲しかった] x^4 4 factorise 281472-X^4-16y^4 factorise

Factorisation is the opposite process of expanding brackets For example, expanding brackets would require \ (2 (x 1)\) to be written as \ (2x 2\) Factorisation would be to start with \ (2x 2\) and end up with \ (2 (x 1)\) The two expressions \ (2 (x 1)\) and \ (2x2\) are equivalent; Factorise a 12 x 4 a 4 x 12 Share with your friends Share 7 a 12 x 4 – a 4 x 12 = a 4 x 4 (a 8We have to factorise x 4y 4 Solution x4 – y 4 cxn ye expressed xs (x 2) 2 – (y2) 2 —(i) We know the identity \(x^{2}y^{2}= (xy)(xy)\) Hence using the

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X^4-16y^4 factorise

X^4-16y^4 factorise-Factorise x^24x4 Updated On 9 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now! Factorise x4 x2 1 Factorise x4 x2 1 how_to_reg Follow thumb_up Like (11) visibility Views (714K) edit Answer question_answer Answers(2) edit Answer person Kishore Kumar Consider x 4 x 2 1 = (x 4 2x 2 1) – x 2 = (x 2) 2 2x 2 1 – x 2 = x 2 1 2 – x 2 It is in the form of (a 2 – b 2) = (a b)(a

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Algebraic Methods wwwnaikermathscom 5 f(x) = 3x3 – 5x2 – 16x 12 (a) Find the remainder when f(x) is divided by (x – 2)(2) Given that (x 2) is a factor of f(x), (a) factorise f(x) completely(4) June 07 Q2 6 f(x) = 2x3 – 3x2 – 39x (a) Use the factor theorem to show that (x 4) is a factor of f (x)(2) (b) Factorise f (x) completely I am trying to factor x 4 1 in to two multiplied polynomials Homework Equations My teacher gave us this hint that its factored form is (ax2bxc)(ax2bxc) The Attempt at a Solution First i assumed that a and c were equal to 1 so that when x 2 is multiplied by the other x 2 is gives me x 4 and 1 times 1 gives me 1This is the same as x 2 0x 4, so you need to find factors of 4 that add up to 0

This is similar to other factorisation problems such as x 2 5x 6 In this problem, you would find prime factors of 6 that add up to 5 (In this case 3, 2) Now, do the exact same with this problem!Factorisation Factorisation class 9 Factorise x^8y^8 Factorise x^4y^4 Factorise x^4y^4 Factorise x^8y^8 Factorise x^2y^2#factorisationofpolynomiaQuotient of x^38x^217x6 with x3;

Add to your resource collection Ref R19 Printable/supporting materials Fullscreen mode Teacher notes Question Solution Question Show that (x2 2y2)2 −4x2y2 =x4 4y4, ( x 2 2 y 2) 2 − 4 x 2 y 2 = x 4 4 y 4, and hence factorise x4 4y4 x 4 4 y 4Factor x^41 x4 − 1 x 4 1 Rewrite x4 x 4 as (x2)2 ( x 2) 2 (x2)2 −1 ( x 2) 2 1 Rewrite 1 1 as 12 1 2 (x2)2 −12 ( x 2) 2 1 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = x2 a = x 2 and b = 1 b = 1 (x2 1)(x2 −1) ( x 2View more examples » Access instant learning tools Get immediate feedback and guidance with stepbystep solutions and Wolfram

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Factorise `(a) x^(4)4x^(2)16 " " (ii) x^(4)4`X 4 − (y z) 4 (x 2) 2 − ((y z) 1) 2 (x 2 − (y z) 2) (x 2 (y x) 2)X^4 324 (x^2)^2 18^2 That would be a perfect square if the term that is twice the product of the square roots of those two terms were added That's 2·18·x^2 or 36x^2 So we add that between those terms and then subtract it That's the same as adding 0 (x^2)^2 36x^2 18^2 36x^2 Factor the first three terms as (x^2 18) (x^2 18) or

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They have the same value for all values of \ (x 3 Let s = x y 2 so x, s, y make an arithmetic progression with difference name it d So x = s − d and y = s d Now E = ( s − d) 4 ( s d) 4 16 s 4 = 2 s 4 12 s 2 d 2 2 d 4 16 s 4 = 18 s 4 12 s 2 d 2 2 d 4 = 2 ( 9 s 4 6 s 2 d 2 d 4) = 2 ( 3 s 2 d 2) 2 Share answered May 1 ' at 1549 Answer3x^2 4x 3x 4x ( 3x 4 ) 1 ( 3x 4 )( 3x 4 ) ( x 1 )hope it helps

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 Factorise 25/4 x^2y^2/9 Updated On To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now! Yes, the four solutions to x^44=0 are x=±1±i So to factor this completely, you have x^44=(x1i)(x1i)(x1i)(x1i) If you multiply the first two factors and the second two factors, you obtain x^44=(x^22x2)(x^2–2x2) Alternatively, if you multiply the first and last factor, and also the second and third, you get x^44=(x^2–2iWhich is what we wanted and hence factorise x4 4y4 x 4 4 y 4 We know that x4 4y4 =(x2 2y2)2 −4x2y2 x 4 4 y 4 = ( x 2 2 y 2) 2 − 4 x 2 y 2 Notice that the right hand side is of the form a2 −b2 a 2 − b 2, where a = x2 2y2 a = x 2 2 y 2 and b =2xy b = 2 x y

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 Factorise x 4 /4 4/x 4 1 Share with your friends Share 3 x 4 4 4 x 4Try typing these expressions into the calculator, click the blue arrow, and select "Factor" to see a demonstration Or, use these as a template to create and solve your own problems Problem 4x2 −9 4 x 2 − 9 Solution (2x3)(2x −3) ( 2 x 3) ( 2 x − 3) Problem x4 −81 x 4 − 81Factoriser Factoriser Enter a quadratic equation to factorise For indices use (^) Factorise Submit

Factorise X4 4 4 X 4 1

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